Don't leave a pinned item when an application starts "when the pinned is a random id"
Hi,
I want have 2 pinned items on the same application but with different command line options.
So, I started both, set random app id on each windows and pinned them in taskbar. OK
Now, if i click on item, app started but random app id is not set and a new item are added on the bar.
Can you fix this ?
Great app
Thanks lot
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AdminRaMMicHaeL (Admin, moved) commented
It works for another programs, but for some reason, not for explorer.
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asdf commented
I can't get this to work. I created 2 shortcuts, one to "explorer.exe C:\dir1" and one to "explorer.exe C:\dir2". I pinned them both to the taskbar. They have different application IDs (Microsoft.AutoGenerated.*).
However when I click on the right-hand pinned shortcut, the window it opens has the same application ID as the left-hand shortcut. This means it replaces the left-hand shortcut in the taskbar, while the right-hand shortcut is still visible. So the right-hand shortcut effectively behaves like a "quick launch" icon, not a pinned application.
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AdminRaMMicHaeL (Admin, moved) commented
I've tried this, and it works fine for me, the two windows don't group.
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n!co commented
I have try this first, but my two shortcuts have the same id and two windows are grouped on the first shortcut item ...
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AdminRaMMicHaeL (Admin, moved) commented
Create a shortcut and pin it instead of pinning the tweaker's random App IDs.